[SQL] 197. Rising Temperature

Table: Weather

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| recordDate    | date    |
| temperature   | int     |
+---------------+---------+
id is the column with unique values for this table.
There are no different rows with the same recordDate.
This table contains information about the temperature on a certain day.

Write a solution to find all dates' id with higher temperatures compared to its previous dates (yesterday).

Return the result table in any order.

The result format is in the following example.

Example 1:

Input: 
Weather table:
+----+------------+-------------+
| id | recordDate | temperature |
+----+------------+-------------+
| 1  | 2015-01-01 | 10          |
| 2  | 2015-01-02 | 25          |
| 3  | 2015-01-03 | 20          |
| 4  | 2015-01-04 | 30          |
+----+------------+-------------+
Output: 
+----+
| id |
+----+
| 2  |
| 4  |
+----+
Explanation: 
In 2015-01-02, the temperature was higher than the previous day (10 -> 25).
In 2015-01-04, the temperature was higher than the previous day (20 -> 30).

To solve this problem, we need to compare the temperature of each day with the temperature of its previous day. Here's how to approach it:

Steps:

Self-Join the Table:
- Join the Weather table with itself (w1 and w2), where the recordDate of w2 is exactly one day before the recordDate of w1.
Compare Temperatures:
- Filter for rows where the temperature on w1.recordDate is greater than the temperature on w2.recordDate.
Select Relevant Columns:
- Retrieve the id of the days that meet the criteria.

SQL Query:

SELECT 
    w1.id
FROM 
    Weather w1
JOIN 
    Weather w2
ON 
    DATE(w1.recordDate) = DATE(w2.recordDate) + INTERVAL 1 DAY
WHERE 
    w1.temperature > w2.temperature;

Explanation:

Self-Join:
- w1 and w2 are aliases for the Weather table.
- The ON clause ensures that w2.recordDate is one day before w1.recordDate.
Filter with WHERE:
- Only include rows where the temperature of w1 is higher than the temperature of w2.
Select w1.id:
- Retrieve the id of the records that satisfy the condition.

Output:

For the given input example:

id	recordDate	temperature
1	2015-01-01	10
2	2015-01-02	25
3	2015-01-03	20
4	2015-01-04	30

The result will be:

id
2
4

Key Points:

The + INTERVAL 1 DAY operation ensures the correct date comparison.
This query works efficiently as there are no duplicate dates in the Weather table.

[SQL] 197. Rising Temperature

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